4x^2+41x=-10

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Solution for 4x^2+41x=-10 equation:


Simplifying
4x2 + 41x = -10

Reorder the terms:
41x + 4x2 = -10

Solving
41x + 4x2 = -10

Solving for variable 'x'.

Reorder the terms:
10 + 41x + 4x2 = -10 + 10

Combine like terms: -10 + 10 = 0
10 + 41x + 4x2 = 0

Factor a trinomial.
(10 + x)(1 + 4x) = 0

Subproblem 1

Set the factor '(10 + x)' equal to zero and attempt to solve: Simplifying 10 + x = 0 Solving 10 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + x = 0 + -10 Combine like terms: 10 + -10 = 0 0 + x = 0 + -10 x = 0 + -10 Combine like terms: 0 + -10 = -10 x = -10 Simplifying x = -10

Subproblem 2

Set the factor '(1 + 4x)' equal to zero and attempt to solve: Simplifying 1 + 4x = 0 Solving 1 + 4x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 4x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 4x = 0 + -1 4x = 0 + -1 Combine like terms: 0 + -1 = -1 4x = -1 Divide each side by '4'. x = -0.25 Simplifying x = -0.25

Solution

x = {-10, -0.25}

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